Oracle 1Z1-805 : Upgrade to Java SE 7 Programmer

시험일은 다가오는데 아직 준비가 부족하다고 느끼시나요? ITDumpsKR의 1Z1-805 연습문제는 Oracle Upgrade to Java SE 7 Programmer의 핵심 포인트만 엄선해 90문항으로 압축했습니다. 짧은 시간 안에 집중적으로 실력을 끌어올려 보십시오.

Oracle 1Z1-805 시험 개요:

Oracle 1Z1-805 시험 요강 주제:

Oracle Upgrade to Java SE 7 Programmer 궁금증 총정리

최신 OCP 1Z1-805 무료샘플문제

문제 #1

Which method or methods should you implement to create your own implementation of the java.nio.file.PathMatcher interface?

A. matches(Path) , fails(Path), enable(boolean)
B. matches(Path)
C. matches(Path), fails(Path)
D. matches(Path) , fails(Path) , setPreferred (String)

문제 #2

Which three enum constants are defined in FilevisitResult?

A. TERMINATE
B. DELETE_CHILD
C. FOLLOW_LINKS
D. NOFOLLOW_LINKS
E. SKIP_SIBLINGS
F. CONTINUE

문제 #3

What are two benefits of a Factory design pattern?

A. Provides a mechanism to monitor objects for changes
B. Eliminates direct constructor calls in favor of invoking a method
C. Eliminates the need to overload constructors in a class implementation
D. Prevents tight coupling between your application and a class implementation
E. Prevents the compile from complaining about abstract method signatures

문제 #4

Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?

A. } catch (IOException | NoSuchFileException e) {
System.out.println(e);
}
B. } catch (IOException | IndexOutOfBoundException e) {
System.out.println(e);
}
C. } catch (Exception | IOException | FileNotFoundException e ) {
System.out.println(e);
}
D. } catch (InvalidPathException | IOException e) {
System.out.println(e);
}
E. } catch (NoSuchFileException e ) {
System.out.println(e);
}

문제 #5

Given:
public class StringApp {
public static void main(String[] args) {
String[] str="Java SE,java EE,Java ME,java FX".split(",");
int count=0;
for(int i=0;i<str.length;i++) {
switch(str[i]) {
case "Java SE":
count++; continue;
case "Java EE":
count++; break;
case "Java ME":
count++; break;
case "Java FX":
count++; break;
}
}
System.out.println("Total match found="+count);
}
}
What is the result?

A. 2
B. 3
C. 1
D. 4

질문과 대답: